- #1
ISU20CpreE
- 69
- 0
I am stuck in this integral please could i get some help or sugestions.
[tex] \int \frac {x+5} {\sqrt{9-(x-3)^2}} * dx [/tex]
If I set:
a= 3
u=(x-3)
[tex] \frac {du} {dx} = 1 [/tex]
du=dx
,and then I don't know what to do.
[tex] \int \frac {x+5} {\sqrt{9-(x-3)^2}} * dx [/tex]
If I set:
a= 3
u=(x-3)
[tex] \frac {du} {dx} = 1 [/tex]
du=dx
,and then I don't know what to do.
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