Explain why the electric field strength is zero

AI Thread Summary
The discussion revolves around calculating the charge on two metal spheres after they come into contact, with one sphere initially carrying a charge of 2Q. The balance reading increases by 2.1 x 10^-3 N when the spheres are separated by 68 mm, prompting the need to apply Coulomb's law to find the charge Q. The user attempts to derive the electric field strength and expresses confusion over their calculations, indicating a misunderstanding of the relationship between force, charge, and electric field. The key point is that the electric field strength is zero at the midpoint between the two charges due to equal and opposite fields canceling each other out. The discussion highlights the importance of correctly applying physics principles to solve for charge and electric field strength.
MightyMeanie
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I am stuck on my physics homework. I can manage the latter question, how ever when i work out the first one my working out has no rhyme nor reason (nor a right answer). Any help will be great.

A small metal sphere on an insulating rod is placed on a top pan balance, as shown in the diagram below. An identical metal sphere carrying a charge of 2Q on an insulating rod is brought into contact with th sphere on the balance so each sphere acquires the same charge.

When the two spheres are a separation of 68 mm, the top of the pan balance reading increases by 2.1 x 10 ^-3 N. Calculate the charge, Q, on each sphere.

Explain why the electric field strength is zero at the midpoint between the two charge.​
 
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sorry just read the sticky after posting
This is how i attempted to do it, but then realized how completely stupid and random it was
F/Q = E = V/d -> v/o = (2.1 x 10 ^ -3) / 2 -> 1.05 x 10 ^-3

(1.05 x 10 ^ -3) / 0.068 = (2.1 x 10 ^ -3) / Q
Q= (2.1 x 10 ^-3) / (1.544 x 10 ^ -3)
= 0.136 C which is stupid
 
Coulomb's law states:

F = (k*q1*q2)/r^2

q1 = Q
q2 = 2Q
r = 68mm
k= Boltzmann constant (See your book for this value)
F = 2.1mN

Solve for Q

Once you have Q it should be easy to figure out the electric field due to each charge.
 
thank you!
 
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