Explain why x-rays source are protons which are accelerated

AI Thread Summary
In a large hadron collider, protons travel in a circular path at near-light speeds, which causes them to accelerate due to the change in direction, despite their speed remaining constant. This acceleration of charged particles leads to the emission of photons, which includes X-rays. The discussion clarifies that the source of X-rays is linked to the acceleration resulting from circular motion, not the speed itself. The key point is that any change in velocity, even if speed is constant, results in the emission of radiation. Therefore, the circular motion of protons is essential for producing X-rays.
thisischris
Messages
26
Reaction score
1
In a large hadron collider at CERN, protos follow a circular path with speeds close to the speed of light. X-rays can be produced by free protons which are accelerating.

Explain why this providesa source of x-rays even though the speeds of the protons are constant.



Provided answer: must be accelerating due to circular motion (1)
(Speed constant but) direction/velocity changing (1)

I'm having trouble understanding how the answer relates to the question. It seems to be indicating that the instantaneous velocity or speed of the proton(s) stays the same but is still accelerating due to circular motion.

However I don't see how this explains the 'source' of x-rays.
 
  • Like
Likes andy0930
Physics news on Phys.org
This is because a charged particle emits photond when accelerated.
You correctly identified that the constancy of speed of the photon was not at all relevant to the non acceleration of the protons, and here is the source of photons.
 
  • Like
Likes andy0930
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top