Exploring the Physics of Stacked Blocks: No Normal Force on Block A

In summary, the three blocks with masses M1, m2, and M3 are kept vertically on top of each other. The normal force exerted by the ground on block C is not experienced by block A because the normal force is simply opposing gravity and there is no net force on block C. The normal force is transferred between blocks C and B, and the same internal forces are acting within each block. The bottom of each block supports all the blocks and the ones above it, while the top of each block supports only the blocks above it. In a position within a block, the weight supported will be between the top and bottom halves. When block C is removed, gravity acts on the blocks, causing them to tumble down. The
  • #1
Shardul Khare
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If 3 blocks have some mass(a,b,c) are kept on one another (Vertically i mean)...Why block a doesn't experience the normal force exerted by the ground on block c? won't that force get transferred through b to a?
 
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  • #2
Shardul Khare said:
If 3 blocks have some mass(a,b,c) are kept on one another (Vertically i mean)...Why block a doesn't experience the normal force exerted by the ground on block c? won't that force get transferred through b to a?

If there were no gravity and the normal force was an active force (someone pushing block c), then some of that force would be transferred through block c to the next block. But, the normal force is simply opposing gravity, so there is no net force on block c.

Of course, some of the force is transferred as the normal force between blocks c and b.

And, there is nothing special about the blocks, the same sort of internal forces are acting within each block. The bottom of each block is supporting all the block and the ones above it, whereas the top of each block is supporting only the blocks above it.
 
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  • #3
PeroK said:
If there were no gravity and the normal force was an active force (someone pushing block c), then some of that force would be transferred through block c to the next block. But, the normal force is simply opposing gravity, so there is no net force on block c.

Of course, some of the force is transferred as the normal force between blocks c and b.

And, there is nothing special about the blocks, the same sort of internal forces are acting within each block. The bottom of each block is supporting all the block and the ones above it, whereas the top of each block is supporting only the blocks above it.
At a position within a block, the weight supported will be between the two. wHAT DOES THATMEAN?
 
  • #4
Shardul Khare said:
At a position within a block, the weight supported will be between the two. wHAT DOES THATMEAN?

I meant in the middle of a block, the weight supported will be the top half of that block plus the blocks above it. There is nothing special about the contact points between the blocks. The same balance of forces is at play throughout each block, eventualy down to inter-molecular forces.
 
  • #5
Shardul Khare said:
hy block a doesn't experience the normal force exerted by the ground on block c?

It does. When you remove block C, don't the rest of the blocks start tumbling down?
 
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  • #6
Vanadium 50 said:
It does. When you remove block C, don't the rest of the blocks start tumbling down?
Isnt that because as C is removed so gravity acts on them? Morever if the force acts on A,Why don't we consider it while drawing the FBD of block A?
 
  • #7
Shardul Khare said:
Isnt that because as C is removed so gravity acts on them? Morever if the force acts on A,Why don't we consider it while drawing the FBD of block A?
Have you drawn free body diagrams of each of the three blocks, showing the forces acting on each, or do you feel that you have advanced to the point beyond which you no longer need to use free body diagrams? If you have drawn the free body diagrams, please write down for us the force balance equation that applies to each of the blocks.
 
  • #8
Assuming the mass of A is M1
Mass of B is m2 and mass of C is M3...As these blocks are kept vertically and are rest

The force acting on the uppermost A would be Gravitaional M1g downwards and the Normal force (N1)exerted by B on A (Equal to m1g) upwardsForces acting on B would be Normal (N1) Exerted by A on B (Third Law) Equal to m1g and gravitational force downwards equal to m2g and the normal (N2) exerted by block C on B ( N2= mig + m2g) upwards

Forces on C would be N2 downwards (Thid law) and m3g as well as N3 upwards(Between ground and C)
 
  • #9
Chestermiller said:
Have you drawn free body diagrams of each of the three blocks, showing the forces acting on each, or do you feel that you have advanced to the point beyond which you no longer need to use free body diagrams? If you have drawn the free body diagrams, please write down for us the force balance equation that applies to each of the blocks.
 
  • #10
Shardul Khare said:
Assuming the mass of A is M1
Mass of B is m2 and mass of C is M3...As these blocks are kept vertically and are rest

The force acting on the uppermost A would be Gravitaional M1g downwards and the Normal force (N1)exerted by B on A (Equal to m1g) upwardsForces acting on B would be Normal (N1) Exerted by A on B (Third Law) Equal to m1g and gravitational force downwards equal to m2g and the normal (N2) exerted by block C on B ( N2= mig + m2g) upwards

Forces on C would be N2 downwards (Thid law) and m3g as well as N3 upwards(Between ground and C)
Excellent. Now you have 3 linear algebraic equations in the three unknowns N1, N2, and N3. Please solve for these three unknowns.
 

Related to Exploring the Physics of Stacked Blocks: No Normal Force on Block A

1. What is the concept behind "No Normal Force on Block A" in stacked blocks?

In stacked blocks, the normal force is the force exerted by one block on another in a perpendicular direction. In this concept, we are exploring the scenario where the bottom block (Block A) does not experience a normal force from the top block, even though it is supporting the weight of the top block.

2. How is this scenario possible?

This scenario is possible due to the principle of superposition in physics. According to this principle, the total force on an object is equal to the vector sum of all individual forces acting on it. In this case, the weight of the top block is balanced by the normal force from the ground, while the weight of the bottom block is balanced by the normal force from the top block. As a result, the normal force on Block A is canceled out and it experiences no normal force from the top block.

3. What factors affect the normal force on Block A?

The normal force on Block A can be affected by the weight and distribution of the blocks, as well as the surface roughness and coefficient of friction between the blocks and the ground. Additionally, any external forces acting on the blocks can also affect the normal force on Block A.

4. How does the lack of a normal force on Block A impact the stability of the stacked blocks?

Without a normal force, Block A may experience a larger displacement or rotation when subjected to external forces. This can lead to a decrease in the stability of the stacked blocks. However, the stability can be maintained by ensuring that the other forces acting on the blocks (such as the weight and friction) are balanced.

5. What are the practical applications of understanding the physics of stacked blocks with no normal force on Block A?

Understanding this concept can have practical applications in engineering and construction, where stacked blocks or other objects are used to support weight and withstand external forces. It can also help in understanding the behavior of structures in various scenarios, such as earthquakes or other natural disasters.

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