Exponential formulation of waves

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The discussion clarifies the transition from the wave representation Acos(kx-ωt) to the exponential form e^{i(kx-ωt)} in both classical waves and quantum mechanics. It highlights that while the exponential form includes an imaginary component, the real part is typically used to represent physical waves, such as electric fields. This practice is largely a convention in classical contexts. In quantum mechanics, the imaginary part is integral to the wavefunction, yet all observable quantities derived from it remain real-valued. Thus, the omission of "Re" in the exponential representation is accepted in both fields for clarity and simplicity.
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Hi all, I'd just like to clear up something that's often confused me.

In classes (particularly classical waves/QM) we've often seen the lecturer switch from describing a wave as (most commonly) Acos(kx-{\omega}t) to e^{i(kx-{\omega}t)}
but doesn't the exponential representation include an imaginary sine term as well? Shouldn't this given wave be represented as ( Re [e^{i(kx-{\omega}t)}])?

If this is the case, is it just a convention that the "Re" is dropped?

Thanks.
 
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As far as I've seen, yes, it's just convention.
 
For classical waves (like E-M waves), yes, it's generally understood that the real part of the expression gives the physical wave (like the electric field value).

For wavefunctions in quantum mechanics, the imaginary part is really part of the wavefunction. All the operations used to find an observable quantity (energy, momentum, probability) from the complex wavefunction still give real-valued results.
 
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