Exponential Integral Homework: Integrating e^(-y)/y

brandy
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Homework Statement


i have to integrate e^(-y) / y
and i found out that you have to use this exponential integral and someone else said it doesn't have an integral. either way I am thoroughly confused

The Attempt at a Solution


i have no clue what so ever. The original question had it in dy/dx=y*e^(x+y) but that above question is all i need help with.
 
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Hi brandy! :smile:

(try using the X2 tag just above the Reply box :wink:)

If you keep integrating by parts, you get a power series times e-y
 
\int\frac{e^{-y}}{y}dy = \int-\frac{e^{-y}}{-y}dy

Let x = -y, then dx = -dy.

\int-\frac{e^{-y}}{-y}dy = \int\frac{e^x}{x}dx

You can rewrite it as the same integral you had in the other thread, which still doesn't have an elementary integral.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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