Express the density of a solid substance varying with temperature

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The density of a solid substance can be expressed as d = d0(1 - 3aT), where d0 is the initial density, a is the thermal coefficient, and T is the temperature change. The volume of the substance changes according to V = V0(1 + 3aT), with mass (m) remaining constant. The relationship indicates that as temperature increases, density decreases due to the expansion of the material. The discussion also suggests assuming that the change in density (d - d0) is negligible for small values of a, allowing for simplification using the binomial theorem. This leads to the conclusion that density varies linearly with temperature changes in the specified form.
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I need to show that the density of a solid substance varies with temperature as d = d0(1 - 3aT), where a is the thermal coefficient and T is the change in temperature.

I know V = V0 (1 + 3aT) and V = m/d. Since m is constant,

d0 = d(1 + 3aT)
d0 - d03aT = d + d3aT - d03aT
d0(1 - 3aT) = d +3aT(d - d0)

Am I now supposed to assume that the d only changes a little compared to d0, so that (d - d0) = 0?
 
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do = d(1 + 3aT)
d = do/(1+3aT) = do(1+3aT)^-1

now expanding using binomial theorem and as a is very small the higher terms can be neglected, gives

d = do(1- 3aT + ...)


MP
 
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