Expressing a surface in cartesian coordinates from spherical

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SUMMARY

The discussion focuses on converting the spherical coordinate equation θ = π/4 into Cartesian coordinates. The relevant equations for conversion are x = r sin(θ) cos(Ø), y = r sin(θ) sin(Ø), and z = r cos(θ). With θ fixed at π/4, the relationship z = r cos(π/4) leads to a specific surface description in Cartesian coordinates. The participant emphasizes the importance of verifying notation, particularly the definitions of θ and Ø, to ensure accurate calculations.

PREREQUISITES
  • Understanding of spherical coordinates and their relation to Cartesian coordinates
  • Familiarity with trigonometric functions and their inverses
  • Knowledge of the equations for converting between spherical and Cartesian coordinates
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the derivation of spherical to Cartesian coordinate transformations
  • Learn about the implications of fixed angles in spherical coordinates
  • Explore the use of trigonometric identities in coordinate transformations
  • Investigate common pitfalls in notation when working with spherical coordinates
USEFUL FOR

Students in mathematics or physics, educators teaching coordinate systems, and anyone involved in geometric modeling or computational geometry.

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Homework Statement


The following equation describes a surface in spherical coordinates. θ =pi/4
Write the equation in the cartesian coordinates?

that is, (r,θ,Ø) to (x,y,z)

Homework Equations


x=rsinθcosØ
y=rsinθsinØ
z=rcosθ

r=sqrt(x^2+y^2+z^2)
θ=cos^-1(z/r)
Ø=tan^-1(y/x)


The Attempt at a Solution


I'm pretty stumped. The only start I can get is that if θ=pi/4, this means that r and phi have to work around this. Allowing r to be from 0 to infinity. I'm not really sure what happens to phi. I'm thinking that it can be anywhere from 0 to 2pi.
 
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If your surface is simply defined as

\theta = \pi/4

then all you need to do is solve your conversion factor from theta of

\theta = cos^{-1}(\frac{z}{r}) = cos^{-1}(\frac{z}{\sqrt{x^{2}+y^{2}+z^{2}}})

Since your value of theta is a constant, you just have

\frac{z}{\sqrt{x^{2}+y^{2}+z^{2}}} = cos(\frac{\pi}{4})

Although you may want to make sure you have your notation correct. Generally I've seen

z = r cos\phi, x = r cos\theta sin\phi, y = r sin\theta sin\phi

and if you did in fact get your notation mixed up (which it's possible that you did or didn't, but it's worth checking) that changes the nature of your calculations.
 
Last edited:

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