- #1

amk_dbz

- 42

- 0

= -pressure(external) . Change in volume

Why is external pressure considered here?

Take for example a closed vessel with weight on apiston having gas enclosed with 200 atm pressure, if the weight is suddenly removed the gas expands against 1 atm external pressure

So why isn't the work done= integral (P(int).dV) which would be larger compared to P(ext).dV?

Any help would be appreciated. :)