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Extreme Sports: Waterboarding and Physics (Work/Tension)

  1. Feb 11, 2008 #1
    Hi, here's an interesting question on EXTREME SPORTS! (tried to make the title interesting)
    hoping someone will verify my work/procedure in solving the que. or put me in the right direction :D Thank you!

    1. The problem statement, all variables and given/known data
    A waterboarder is at an angle of 25 degrees with respect to the straight central path of a top speed motor boat. She's being pulled at a constant speed of 18m/s. If the tension of her tow rope is 100N
    i) How much work does the tope do on the boarder in 10.0s
    ii) How much work does the resistive force of the water have on her in the same amount of time


    2. Relevant equations
    W=Fd=F(cos[tex]\vartheta[/tex])d
    v=d/t



    3. The attempt at a solution
    i) v=d/t therefore d=vt
    d=(10.0s)(18m/s)=180m travelled
    W=Fd
    =(100N)(180m)
    =18kJ

    ii) d=180m/s
    W=Fd=F(cos[tex]\vartheta[/tex])d
    W=(100N)(cos25)(180m)
    =16.3kJ
     
  2. jcsd
  3. Feb 12, 2008 #2
    I've added a diagram, hope this helps
     

    Attached Files:

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