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cse63146
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Homework Statement
A 100-turn, 2.0-cm-diameter coil is at rest in a horizontal plane. A uniform magnetic field away from vertical increases from 0.50 T to 1.50 T in 0.60 s. What is the induced emf (in mV) in the coil?
Homework Equations
[tex]\Phi_m = ABcos\vartheta[/tex]
[tex]E = \frac{d \Phi}{dt}[/tex]
The Attempt at a Solution
[tex]E = \frac{d \Phi}{dt} = \frac{d (ABcos\vartheta)}{dt} = - \pi r^2 \frac{dB}{dt}sin\vartheta[/tex]
[tex]\frac{dB}{dt} = \frac{1}{.6} = 1.67 T[/tex]
I can "ignore" the negative sign because I just need the absolute value, and the derivative of cos = -sin
*I forgot the number ot turns in the previous equation, but I added them in the next one*
[tex]N \pi r^2 \frac{dB}{dt}sin\vartheta = (100) \pi 0.1^2 (1.67) sin60 = 45mV[/tex]
Did I make any mistakes?