Faraday's law with loop of wire and resistor

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Homework Help Overview

The discussion revolves around applying Faraday's law to a coil placed in a time-varying magnetic field. The problem involves calculating the current through a resistor connected to the coil, given specific parameters such as the coil's radius, number of turns, and the magnetic field's time dependence.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the induced emf calculation and the necessity of considering the number of turns in the coil. There is also a suggestion to consider self-inductance in the context of the problem.

Discussion Status

The discussion is ongoing with participants exploring different aspects of the problem. Some have provided guidance regarding the inclusion of the number of turns in the emf calculation, while others are questioning whether self-inductance should be factored into the analysis.

Contextual Notes

There is an indication that the course material may include concepts of self-inductance, which could influence the approach to the problem. Additionally, the original poster has expressed difficulty in arriving at the correct answer despite following a specific method.

xSpartanCx
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A coil 3.65 cm radius, containing 560 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×10^−2 T/s)t+( 3.05×10^−5 T/s4)t^4. The coil is connected to a 600-Ω resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil.
What is the current in the resistor at time t0 = 4.50 s ?I got the correct induced emf value:
E= 2.81×10^−2 V +( 2.86×10^−4 V/s3 )t^3

I've tried plugging in 4.5s into the emf equation and then dividing I = V/R but the answer is incorrect.
 
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xSpartanCx said:
I got the correct induced emf value:
E= 2.81×10^−2 V +( 2.86×10^−4 V/s3 )t^3
Did you multiply it by the no of turns(560)?
 
cnh1995 said:
Did you multiply it by the no of turns(560)?
Yes, that's part of the emf value.
 
Has your course covered self-inductance?
Perhaps you're expected to include the factor E = - L di / dt.
 

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