Fermi Paradox Solution: R1/C1 < R2/C2

  • Thread starter Thread starter Dbwh
  • Start date Start date
  • Tags Tags
    Fermi Paradox
Dbwh
Messages
1
Reaction score
0

Homework Statement



In the book "In searcg of life in the Universe" A.D. Ursula gave the following formula

R1/C1 = R2/C2 (A)

when the contact between two civilizations happens, where R - result from a contact and C - cost to make a contact for those civilizations.

Homework Equations



The key equation is

R1/C1 = R2/C2

The Attempt at a Solution



Let R1 and C1 be result and cost for Earth.

There is great silence because

R1/C1 < R2/C2 (B)

If it were otherwise it would mean that the contact already happened but there is a great silence.

Hence equation (B) is fulfilled.
 
Physics news on Phys.org
Was there a question?

Obviously the equation is of little use, we
don't learn the value of R until after we've spent C ( and even C is subject to change).

R could be absolute utopia or total destruction. But I, for one, am interested in finding out :smile:
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top