Ferris Wheel Weight Calculation

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A discussion on Ferris Wheel weight calculations reveals confusion regarding apparent weight at different positions on the ride. A 250lb student experiences an apparent weight of 250lb at the top, but this weight decreases at the top due to centripetal forces, leading to a calculated weight of 225lb. If the speed of the Ferris wheel is tripled, the apparent weight at the top would increase significantly, potentially calculated as 2250lbs based on the formula involving mass, speed, and radius. Participants clarify that the weight changes due to the wheel's rotation and that the original question may have contained a typo. Understanding the physics of centripetal force is essential for accurate weight calculations on a Ferris wheel.
Kharmon7814
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Ferris Wheel ...Trick Question?

This is one of those that might be a typo or I am really missing something. A 250lb student is riding on a steadily rotating Ferris Wheel. If the student has an apparent weight of 250lb at the top what will be the students apparent weight at the bottom? What would be the apparent weight of the student at the top if the speed of the Ferris wheel were exactly tripled?
If the weight is the same at the top as it normaly is then all the forces are equaling out so there wouldn't be a change in weight anywhere on the wheel. Right? As for tripling the speed his weight would increase by a factor of 9 so it would be 2250lbs. Am I on the right track here? Thanks for the help
 
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Are you sure with the question.Because student with original weight 250 lb will have weight less than 250lb at the top of the wheel provided the wheel move with constant speed.

because the new weight becomes=250-m(v^2/r)
m=mass of student
v=speed of the wheel
r=radius of the wheel

it is possible to have the same weight if only when speed is zero.but the question says"steadily rotating Ferris Wheel".So I am questioning that part.
 
It was a typo

The weight of the student was 225 at the top. Having all the info makes the problem much easyer.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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