- #1
Hymne
- 89
- 1
Hello fellow physicists!
I'm currently trying to learn some QFT and the reader gives an introduction by expressing the non-relativistic hamiltonian with integral and creation, destruction operators.
Later he writes:
|Psi, t > = \int d3x1...3xn Psi(x1, ..., xn; t) a+(x1) ... |0>
And i´m not really sure how to think about this. Isn't |Psi, t > the wavevector of Psi(x1, ..., xn; t) ?
Please give me some handwaving or mental words about why this is true..
I'm currently trying to learn some QFT and the reader gives an introduction by expressing the non-relativistic hamiltonian with integral and creation, destruction operators.
Later he writes:
|Psi, t > = \int d3x1...3xn Psi(x1, ..., xn; t) a+(x1) ... |0>
And i´m not really sure how to think about this. Isn't |Psi, t > the wavevector of Psi(x1, ..., xn; t) ?
Please give me some handwaving or mental words about why this is true..