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## Main Question or Discussion Point

Hello fellow physicists!

I'm currently trying to learn some QFT and the reader gives an introduction by expressing the non-relativistic hamiltonian with integral and creation, destruction operators.

Later he writes:

|Psi, t > = \int d

And i´m not really sure how to think about this. Isn't |Psi, t > the wavevector of Psi(x

Please give me some handwaving or mental words about why this is true..

I'm currently trying to learn some QFT and the reader gives an introduction by expressing the non-relativistic hamiltonian with integral and creation, destruction operators.

Later he writes:

|Psi, t > = \int d

^{3}x_{1}...^{3}x_{n}Psi(x_{1}, ..., x_{n}; t) a^{+}(x_{1}) ... |0>And i´m not really sure how to think about this. Isn't |Psi, t > the wavevector of Psi(x

_{1}, ..., x_{n}; t) ?Please give me some handwaving or mental words about why this is true..