Final temperature of sliver ring in calorimeter

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To find the final temperature of the silver ring in the calorimeter, the heat transfer equation Q = mcΔT is applied, considering both the silver ring and the water. The silver ring, initially at 84 degrees C, loses heat while the water, starting at 24 degrees C, gains heat. A total of 0.140 kJ of energy is lost to the surroundings, which must be accounted for in the calculations. The heat lost by the silver ring must equal the heat gained by the water, minus the energy lost to the surroundings. The final temperature will be lower than the initial temperature of the water due to this energy loss.
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A 25.5 g silver ring (Cp = 234 J/kg times degrees C) is heating to a temperature of 84 degrees C and then placed in a calorimeter containing
5 x 10 to the negative 2 power kg of water at 24 degrees C. the calorimeter is not perfectly insulated, however, a 0.140 kJ of energy is transferred to the surroundings before a final temperature is reached. What is the final temperature?
 
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try this Q = m c \Delta T and think about which is transferring the energy and which is receiving the energy...then consider the amount of energy lost to the surroundings and how that would affect the final temp.
 
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