Find center of mass of solid uniform density

haxtor21
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Homework Statement


Find the center of mass of the solid of uniform density bounded by the graphs of the equations: Wedge: x^2+y^2=a^2. z=cy(c>0), y>=0, z>=0


Homework Equations



Mx=int(y*p(x,y) dA)
dA=area of integration, dydx/dxdy

The Attempt at a Solution



I set up all the equations for Mx, My and x-bar, y-bar but I can't seem to realize what the limits of integration are. I can't see how the z=cy comes into play at all. Does it imply its a 3 dimensional figure or what?
 
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hi haxtor21! :smile:

(have an integral: ∫ and try using the X2 and X2 icons just above the Reply box :wink:)
haxtor21 said:
… I can't see how the z=cy comes into play at all. Does it imply its a 3 dimensional figure or what?

it's a vertical cylinder (x2 + y2 = a2), sliced by a plane through the x-axis and sloping at 45° :smile:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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