Find Diameter of Tungsten Filament of Resistance 0.041

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SUMMARY

The discussion centers on calculating the diameter of a tungsten filament with a resistance of 0.041 ohms and a length of 2.5 cm. The resistivity of tungsten is given as 5.6 × 10-8 Ω·m. The formula used is R = ρ(L/πr2), which was rearranged to find the radius. The initial calculation yielded an incorrect result of 2.0856e-4, indicating a potential error in decimal placement during the square root operation.

PREREQUISITES
  • Understanding of electrical resistance and resistivity
  • Familiarity with the formula R = ρ(L/πr2)
  • Basic algebra for rearranging equations
  • Knowledge of unit conversion (cm to m)
NEXT STEPS
  • Review the derivation of the resistance formula R = ρ(L/πr2)
  • Practice unit conversion between centimeters and meters
  • Learn about the properties of tungsten and its applications in electronics
  • Explore common mistakes in algebraic manipulations in physics problems
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Students studying physics, particularly those focusing on electrical properties and resistive materials, as well as educators looking for examples of resistance calculations.

bob12345
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Homework Statement



A 2.5 cm length of tungsten filament in a
small lightbulb has a resistance of 0.041
.
Find its diameter. (The resistivity is
5.6 × 10−8
· m).
Answer in units of mm.

Homework Equations


R=p(L/pi*r^2)


The Attempt at a Solution


i have reworked the equation to the square root of pL/R*pi equals r and then multiplied that answer by 2 which nds u being 2.0856e-4 but it is not right??
 
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Welcome to PF!

Hi bob12345! Welcome to PF! :smile:

(have a pi: π and a rho: ρ and try using the X2 tag just above the Reply box :wink:)

Method seems ok :smile:

have you just got the decimal point in the wrong place before square-rooting?
 
i didnt think so because i converted the length to meters..
 

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