Find gradient at a point and the directional derivative Multivariable calculus

Nugget3
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Calculate gradient of f
f(x,y)=x^3+2y^3
at point P (1,1)
and the directional derivative at P
in the direction u of the given vector A -> i-j

I tried to attempt this but i honestly don't know where to start. I began to take the partial derivatives of f. I got f'=3x^2dx+6y^2dy, however that answer doesn't seem correct to me.
 
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Nugget3 said:
Calculate gradient of f
f(x,y)=x^3+2y^3
at point P (1,1)
and the directional derivative at P
in the direction u of the given vector A -> i-j

I tried to attempt this but i honestly don't know where to start. I began to take the partial derivatives of f. I got f'=3x^2dx+6y^2dy, however that answer doesn't seem correct to me.

What you have calculated is the total differential of f(x,y), which includes both partials ##f_x## and ##f_y##. What is the formula for the directional derivative? Show us what happens when you try to calculate it.
 
it is the dot product of the gradient at P with a unit vector in the given direction
 
LCKurtz said:
What you have calculated is the total differential of f(x,y), which includes both partials ##f_x## and ##f_y##. What is the formula for the directional derivative? Show us what happens when you try to calculate it.

hedipaldi said:
it is the dot product of the gradient at P with a unit vector in the given direction

You ignored the part I highlighted in red.
 
try to calculate what?don't you need to calculate the directional derivative?
 
hedipaldi said:
try to calculate what?don't you need to calculate the directional derivative?

Yes. You posted a question because you were apparently stuck on the problem. You have now stated that you need to take the gradient at P dotted into a unit vector. So please do it and show us what exactly you are stuck on.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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