Find initial Velocity with only distance, angle, and acceleration.

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Homework Help Overview

The problem involves a projectile launched from a cannon towards a target located 1580 m away, at an angle of 24° with the horizontal, under the influence of gravity (9.8 m/s²). The task is to determine the initial velocity, the maximum height of the trajectory, and the time taken to reach the target, without considering friction.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss relevant equations for projectile motion and attempt to derive relationships between initial velocity, time, and range. Some express difficulty in solving the problem, while others suggest finding time in terms of initial velocity and substituting it into the range equation.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to relate the variables involved. Some guidance has been offered regarding the use of equations and the relationship between time and initial velocity, but no consensus has been reached on a complete solution.

Contextual Notes

There is a noted constraint regarding the lack of an explicit value for the initial velocity, which is central to solving the problem. Participants are working under the assumption that friction is negligible.

Jimkatz809
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Homework Statement


A cannon sends a projectile towards a target
a distance 1580 m away. The initial velocity
makes an angle 24◦ with the horizontal. The
target is hit.
The acceleration of gravity is 9.8 m/s2 .
What is the magnitude of the initial veloc-
ity?
Answer in units of m/s.

How high is the highest point of the trajec-
tory?
Answer in units of m.

How long does it take for the projectile to
reach the target? (Assume no friction)
Answer in units of s.


Homework Equations





The Attempt at a Solution

 
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Collect the relevant equations for projectile motion from any source.
 
Ive spent about 2 hours trying and trying this problem but i can't figure out the answers.
The equations i used were
Vox=VoCos0o
Voy=VoSin0o
V^2=Vo^ plus 2a(x-xo)
V=Vo plus at
 
Since there is no acceleration in the x direction, vox remains constant.
Using the last equation you can find the time to reach the maximum height. Here V = 0, Voy = Vosinθ and a = g.
Double that time is the time of flight t.
Range of the projectile R = Vo*cosθ* t
 
Vo is not given
 
Jimkatz809 said:
Vo is not given
First of all find t in terms of Vo, sinθ and g. substitute this value in the expression for R and solve for Vo.
 

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