Find Max Torque Using Smaller Rad of Shaft

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The discussion centers on understanding why the smaller radius of a shaft is used to calculate maximum torque instead of the larger radius. The formula for shear stress directly relates torque to the radius, suggesting the largest radius would be appropriate; however, the torque is applied at the thinner part of the shaft. It is clarified that shear stress is relevant to the surface being pulled on, which in this case is the smaller radius. The smaller radius must transmit the same torque as the larger part, highlighting the importance of the specific application point of the torque. This insight resolves the initial confusion regarding the use of shaft radii in torque calculations.
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Homework Statement


The question wants me to find the maximum torque.
I do not understand why the solution uses the radius of the smaller part of the shaft rather than the radius of the thicker part of the shaft. Please see the attached image.

Homework Equations



shear stress = (max torque)(maximum radius)/J where J = polar moment of inertia.

J = π/2c^4 where c = max radius of the rod

The Attempt at a Solution



I want to use 37.5mm as the radius (radius of larger part of the shaft), but it is not correct. The formula above directly relates torque T and c (radius), which is why I would assume it would be correct to use the largest c value possible. I would appreciate any insight. Thanks.
 

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I do not understand why the solution uses the radius of the smaller part of the shaft rather than the radius of the thicker part of the shaft.
Probably because the diagram shows the torque being applied to the thin part of the shaft.

It's shear stress you are calculating - the bigger part of the shaft may get a torsional (corkscrew) and a centrifugal stress - but to get a shear stress, something has to be pulling on the surface.
I suspect you are just taking your equation too literally - go back to the definition of a shear force and see how that applies to a torque. i.e. what if you applied the torque to the inner surface of a hollow shaft?
 
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Simon Bridge said:
Probably because the diagram shows the torque being applied to the thin part of the shaft.

Should have seen that, haha. Thank you.
 
The smaller radius shaft must transmit the same torque as the larger radius part.
 

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