Find Net Capictance: Capacitor C

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To find the net capacitance between points A and B, it is confirmed that there is a connection at the intersection in the provided diagram. Initially, one capacitor is identified as ineffective due to a zero voltage drop, leaving three capacitors for analysis. The first two capacitors are in parallel from A to the midpoint, while the third capacitor is in series from the midpoint to B. The total capacitance can be calculated by adding the capacitances of the capacitors in parallel and then incorporating the series capacitor. This method effectively simplifies the process of determining the net capacitance between the two points.
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each capacitor has capictance c

find net capictance b/w a and b

http://img17.imageshack.us/img17/5720/13481036.gif
 
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Is that intersection in the middle a contact? Or are those two wires not crossing?
 
yes there is connection between those 2 points
 
Alright, well after some time passes there will be no current. You will have a voltage drop from A to B, called V. If there is one capacitor between A and B, then you know the drop across the capacitor is just V. So that helps you solve for 2 capacitors.

The capacitor to the bottom left is useless since its voltage drop is just 0 (so its charge is 0).

That leaves the top 3 capacitors. The first two are connected in parallel from A to the midpoint. Then they are connected in series with the last capacitor to B. Once you get the net capacitance there...

You know those are now in parallel with the two capacitors we initially discussed. So you can just add their capacitances all up.

Sorry about all the text, would have helped if you labelled the capacitors in the pic.
 
thanks buddy , i got it.
 
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