- #1

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The direction of the incident is:

[tex]\hat n_i \;=\; \hat x sin \theta_i + \hat z cos \theta_i \;\hbox { and direction of }\; \hat {E_i} \;= \hat x cos \theta_i - \hat z sin \theta_i [/tex]

I know

[tex] \hat {E_r} \;=\; \hat x cos \theta_i + \hat z sin \theta_i [/tex]

My question is how can I derive the direction of [itex] \vec {E_r}[/itex] by using formulas? I got this by looking at the reflection as I move the incident

**E**towards the boundary...by drawing. I want to find this mathametically. Please help.

Thanks

Alan