Find Pendulum Period & Frequency: 35 Oscillations in 12 Secs

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To find the period of a pendulum making 35 oscillations in 12 seconds, divide the total time by the number of oscillations, resulting in a period of 0.343 seconds per oscillation. The frequency, calculated as the number of oscillations per second, is approximately 2.92 Hz. The discussion also touches on how the period of a pendulum may change when a plane ascends to a cruising altitude of 10,000 meters, although specific calculations for this scenario are not provided. Understanding the relationship between period and frequency is crucial for solving these problems. The conversation highlights the need for clarity in applying these concepts to different scenarios.
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can someone explain how to find the period of a pendulum when given only the time?

how do you find the period of a pendulum that makes 35 oscillations in 12 seconds? also the frequency?

a simple pendulum can be used as an altimeter on a plane. how will the period of the pendulum cary as the plane moves from the runway to its cruising altitued of 1.00x10^4 meters?
 
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lexi_love said:
how do you find the period of a pendulum that makes 35 oscillations in 12 seconds? also the frequency?

35 oscillations in 12 seconds


Periodic time is the time taken for one oscillation

Frequency is the number of oscillations per second
 
sweet. thanks. that helps alot. do you know anything about the other problems?
 
Sorry, I have some ideas but I think I am over thinking it...so that's a no
 
mmk. thanks..let me know if you figure it out please. =]
 
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