Find the Atom and Mole Ratios for Compound CH3COOC2H5 | Quick Help

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The discussion revolves around determining the atom and mole ratios of carbon (C) to oxygen (O) in the compound CH3COOC2H5. Participants clarify that the atom ratio is based on the number of each type of atom present in the molecule, while the mole ratio relates to the number of moles of these atoms in a balanced reaction. There is confusion regarding the concept of mole ratios, particularly when substances are not in molecular form, leading to a need for assumptions in calculations. The importance of focusing on the specific question about the number of carbon and oxygen atoms in the compound is emphasized. Overall, the thread highlights the need for clarity in understanding chemical ratios and encourages users to engage directly in the forum rather than seeking private communication.
ASMA HASSAN
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1. Homework Statement [/b]
on this compound ( CH3COOC2H5)
what is the
1) atom ratio of C to O ?
2) mole ratio of the same
 
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How many carbon atoms? How many oxygen atoms?
 
can i add you on my email..
to help me easier?
 
Please show the work.

Borek provided the method for part 1.

How are atoms and moles related?
 
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please i have more question..

can i get your email?
 
ASMA HASSAN said:
please i have more question..

can i get your email?
Please do not request emails. Please ask questions in the forum in the thread. That is the point of the forum.
 
i need them fast .. so, can you concentrate with me??
 
Chemistry is not my subject, but I thought a "mole ratio" was simply the numerical ratio of the number of moles of molecules needed to make a balanced reaction, or in certain cases where the substance doesn't come in molecules, it's in terms of the basic unit, atom or ionic formula. (It can then be multiplied by the molecular or unit weight to determine appropriate ratios of masses of reactants). For example, if the reactants are hydrogen and oxygen gases (H2 and O2) forming water (H2O) then the mole ratio of hydrogen to oxygen is 2:1, the same as the atom ratio, but if one is reacting solid carbon (where the unit is C) with oxygen gas (O2) to make carbon dioxide (CO2) then the mole ratio is 1:1 but the atom ratio is 1:2. Can a chemist confirm that this is correct?

Since O is not a molecule, and for that matter neither is C the "mole ratio" part of this question doesn't make much sense to me, and appears to require an additional assumption. I would personally state my assumption and answer the question on that basis.
 
Jonathan Scott said:
Chemistry is not my subject, but I thought a "mole ratio" was simply the numerical ratio of the number of moles of molecules needed to make a balanced reaction, or in certain cases where the substance doesn't come in molecules, it's in terms of the basic unit, atom or ionic formula. (It can then be multiplied by the molecular or unit weight to determine appropriate ratios of masses of reactants). For example, if the reactants are hydrogen and oxygen gases (H2 and O2) forming water (H2O) then the mole ratio of hydrogen to oxygen is 2:1, the same as the atom ratio, but if one is reacting solid carbon (where the unit is C) with oxygen gas (O2) to make carbon dioxide (CO2) then the mole ratio is 1:1 but the atom ratio is 1:2. Can a chemist confirm that this is correct?

When explaining moles I like to refer to the mole as "overgrown dozen" - just like dozen is 12 objects, mole is 6.02*1023 objects. You may have dozen atoms, dozen molecules, you may have mole of atoms, mole of atoms. Generally speaking you may have mole of cars (not that it makes any sense, but technically that's correct).

Since O is not a molecule, and for that matter neither is C the "mole ratio" part of this question doesn't make much sense to me, and appears to require an additional assumption. I would personally state my assumption and answer the question on that basis.

See above - mole doesn't have to refer specifically to chemically sound molecules (although it usually does). In this case it just refers to the ratio of numbers of atoms.
 
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ASMA HASSAN said:
i need them fast .. so, can you concentrate with me??

If you need it fast, then get to work using what you have been told already.

To solve this question you need to answer Borek's question from post #2: how many C atoms and how many O atoms are in the molecule CH3COOC2H5 ? Spending time on anything else (like asking for the email address of anybody who will talk to you) is not a good use of your time.
 

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