- #1

- 4,300

- 53

## Main Question or Discussion Point

For a parallel polarization EM hitting the conductor boundary in an oblique angle. z axis is perpendicular to the boundary and point into the conductor. y-axis it out of the page which give x pointing up. Let the boundary surface by xy plane. With this:

The direction of the incident is:

[tex]\hat n_i \;=\; \hat x sin \theta_i + \hat z cos \theta_i \;\hbox { and direction of }\; \hat {E_i} \;= \hat x cos \theta_i - \hat z sin \theta_i [/tex]

I know

[tex] \hat {E_r} \;=\; \hat x cos \theta_i + \hat z sin \theta_i [/tex]

My question is how can I derive the direction of [itex] \vec {E_r}[/itex] by using formulas? I got this by looking at the reflection as I move the incident

Thanks

Alan

The direction of the incident is:

[tex]\hat n_i \;=\; \hat x sin \theta_i + \hat z cos \theta_i \;\hbox { and direction of }\; \hat {E_i} \;= \hat x cos \theta_i - \hat z sin \theta_i [/tex]

I know

[tex] \hat {E_r} \;=\; \hat x cos \theta_i + \hat z sin \theta_i [/tex]

My question is how can I derive the direction of [itex] \vec {E_r}[/itex] by using formulas? I got this by looking at the reflection as I move the incident

**E**towards the boundary......by drawing. I want to find this mathametically. Please help.Thanks

Alan