# Find the Electric field due to two curved rods

1. Jan 29, 2014

### LeFerret

1. The problem statement, all variables and given/known data
Two curved plastic rods, together form a circle of radius r. The top half of the circle is the first rod with charge -q, the bottom half of the circle is the other rod with charge q. Find the magnitude and direction of the electric field at point P, at the center of the circle.

2. Relevant equations
dE=k∫dq/r2

3. The attempt at a solution
I'm wondering if my assumptions are correct.
So since the top half of the circle has charge -q, the electric field would go towards the rod, away from the center so it would not contribute.
The bottom half of the circle has charge +q, so the electric field would be directed away from the rod, towards the center of the circle.
By symmetry the x-components of the field would cancel and we would have only the y-components.
Therefore dE=dEy=dEsinθ=k∫dqsinθ/r2
we know that λdx=dq
but we know that dx=rdθ, so by substitution I would have, dq=λrdθ
also λ=q/x=q/(rθ)
so dq=qrdθ/(r*pi)
for my limits of integration I would go from pi to 2pi
does all of this seem reasonable? or is it completely off?

Last edited: Jan 30, 2014
2. Jan 30, 2014

### LeFerret

Figured out my mistake. Can't assume that the top rod contributes no field.