Two positive point charges each have a charge of +q and are fixed on the y axis at y = +a and y = -a. (Use k, q, a, and x as necessary.)(adsbygoogle = window.adsbygoogle || []).push({});

(a) Find the electric potential at any point on the x axis.

V = 2kq/[sqrt(x^2+a^2)]

(b) Use your result in part (a) to find the electric field at any point on the x axis.

For part B, would I differentiate the potential with respect to x? If so, my answer would be (-2xkq)/[(x^2+a^2)^(3/2)]

If you can please, I'm also having trouble understanding why the electric field is the derivative of the potential with respect to its distance..

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# Homework Help: Find the electric potential at any point on the x axis

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