Find the magnitude of acceleration of the puck on the ramp

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SUMMARY

The problem involves calculating the magnitude of acceleration of a 0.20 kg hockey puck launched up a metal ramp inclined at a 30.0-degree angle, with static and kinetic friction coefficients of 0.40 and 0.30, respectively. The correct approach requires applying Newton's second law (F = ma) and accurately resolving gravitational forces into components. The user initially miscalculated the normal force and the frictional force, leading to an incorrect acceleration value of -1.4 m/s². The correct calculation should yield a positive acceleration value after properly applying the forces in both the x and y directions.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of trigonometric functions (sine and cosine) for angle resolution
  • Familiarity with the concepts of static and kinetic friction
  • Ability to resolve forces into components on an inclined plane
NEXT STEPS
  • Review the calculation of normal force on an inclined plane
  • Study the effects of friction on motion in inclined systems
  • Learn about vector resolution of forces in two dimensions
  • Practice similar physics problems involving inclined planes and friction
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and inclined plane problems, as well as educators seeking to clarify concepts of force resolution and friction in motion.

ScullyX51
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Homework Statement


A .20 kg hockey puck is launched up a metal ramp that is inclined at a 30.0 degree angle. The coefficients of static and kinetic friction between the hockey puck and the metal ramp are
Ms= .40 kg and Mk=.30 kg , respectively. The puck's initial speed is 35.0 m/s. What is the magnitude of the acceleration of the puck on the ramp?

Homework Equations


F= ma


The Attempt at a Solution


N= Nj
Fgrav= mg(cos 30- sin 30)
Friction= MkN

In the j direction the forces are:
N-mgsin(30)=0
N= -1.94
In the i direction the forces are:
mgcos(30) + MkN=ma
a= (mgcos(30)+ MkN)/ m =a

then when I plug in all of the given numbers I get -1.4.
I have tried this problem a bunch of times and cannot get anywhere close to the correct answer. What am I doing wrong?
 
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ScullyX51 said:

Homework Statement


A .20 kg hockey puck is launched up a metal ramp that is inclined at a 30.0 degree angle. The coefficients of static and kinetic friction between the hockey puck and the metal ramp are
Ms= .40 kg and Mk=.30 kg , respectively. The puck's initial speed is 35.0 m/s. What is the magnitude of the acceleration of the puck on the ramp?

Homework Equations


F= ma


The Attempt at a Solution


N= Nj
Fgrav= mg(cos 30- sin 30)
Friction= MkN

In the j direction the forces are:
N-mgsin(30)=0
N= -1.94
In the i direction the forces are:
mgcos(30) + MkN=ma
a= (mgcos(30)+ MkN)/ m =a

then when I plug in all of the given numbers I get -1.4.
I have tried this problem a bunch of times and cannot get anywhere close to the correct answer. What am I doing wrong?
mostly you've got your mgsin30 and mgcos 30 mixed up.
 

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