Find the Mass of Ice Needed to Cool 800mL Water to 0.0°C

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Homework Help Overview

The problem involves determining the mass of ice needed to cool a specific volume of water from an initial temperature to 0.0°C. The subject area includes thermodynamics and heat transfer principles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between volume and mass, particularly questioning how to convert the given volume of water to mass using its density. There is also an exploration of the energy required to change the temperature of the water.

Discussion Status

The discussion is ongoing, with participants offering hints and raising questions about the necessary calculations and conversions. Some guidance has been provided regarding the density of water, but no consensus has been reached on the overall approach to find the mass of ice needed.

Contextual Notes

Participants note the specific volume of water and its initial temperature, as well as the temperature of the ice. There is an emphasis on the need to consider energy changes in the system.

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Homework Statement


Ice at 0.0°C is mixed with 8 × 102 mL of water at 28°C. How much ice must melt to lower the water temperature to 0.0°C?


Homework Equations



Q = mc(delta)T

The Attempt at a Solution



c = 4.184 J/g K
(delta)T = -28C
V = 800 mL

I'm not sure what to do since the volume is given and not the mass in this problem.
 
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HINT: What is the density of water?
 
ok, but now how do you find how much ice is needed? when density = mass/v and the density of water is 1000kg/m^3 =mass / 800mL
 
You first need to work out how much energy is required to change the temperature of 816 mL of water by 28oC.
 

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