Find the moment of inertia

  • Thread starter rcmango
  • Start date
  • #1

Homework Statement

heres a very messy drawing for an idea of what were looking at: [Broken]

area moment of inertia Ix0 of a rectangle about the axis x0 that passes through the centroid is: Ix = 1/12bh^3

the moment of inertia about an axis x that is parallel to the x0 is given by: Ix = Ix0 + Ad^2x

where A is the area of the rectangle, and dx is the distance between the two axes.

the inputs are width w, height h, and thickness t.

w = 200mm h = 300 mm, and t = 22mm

find the moment of inertia:

Homework Equations

Ix0 = 1/12bh^3

Ix = Ix0 + Ad^2x

The Attempt at a Solution

my questions are..

is t the what plugs into b in this problem?

also, is area of the rectangle just Base * height, so 200 * 300?

not sure how to find the distance between the two axis.

please help.
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Answers and Replies

  • #2
help please?
  • #3
Gib Z
Homework Helper
Re draw your diagram. The reason no one is helping is because instantly, when they see something thats too hard to read, they wont bother. I know thats what I thought when I saw the picture..
  • #4
I didnt get your drawing, but from the wording it seems you need to use the parallel axis theorem. If [tex]I_{cm}=I_0[/tex] about a certain axis, then [tex]I_x=I_0+mx^2[/tex], where x is the distance of the shifted axis from the axis of the center of mass (With moment of inertia [tex]I_0[/tex]).
  • #5
how were you able to draw that. Is that found on image shack or somewhere on your computer. sorry for the off-topic comment
  • #6
Thanks anyways, I was able to figure this out eventually.

Sorry for the awkward drawing. I used paintbrush to draw it, then hosted it through imageshack. However, i recommend hosting a bmp file instead of a low quality jpeg.