Find the power in the circuit

[jojobananas]

My biggest issue is I don't know what to do with the ix
So I really just need to know how to calculate power for C and E. Thank you!

 

[Zryn]

The ix current is given as 3A, but it is in the opposite direction, so we say ix = -3A.

E is a Current Controlled Voltage Source (CCVS) which has the voltage across it depending on the current ix. We know ix = -3A so V(E) = 2 * ix = -6V.

This doesn't make sense for the circuit though, as we need E = 6V for the law of conservation of energy not to be violated, so pretend E = 6V for your calculation.

 

[jojobananas]

thank you!

 

[NascentOxygen]

My biggest issue is I don't know what to do with the ix

Actually, I think you could ignore it! * :uhh:

Simply because you know the current through each of the elements, and you know the magnitude of the voltage across each, so for each P=V.I

Okay, you may not have been told the voltage across that rhombus-thing
but the element in the centre has 10volts, and that on the right has 4volts, leaving (paying close attention to polarities) 6volts across the rhombus. (I must admit I didn't recognize it as a CCVS until Zryn pointed that out.)

It's not clear whether you need to attach a + or - sign to each power calculation, to indicate whether a power source or sink. If in doubt, it won't hurt to do so.

*you can do this in this case because there seems to have been more information provided on I's and V's than absolutely necessary

 

[DeeNos]

To calculate power in a circuit, you need to know the voltage (V) and current (I) at each component. Power is calculated using the formula P = VI.

In this case, to find the power for component C and E, you would need to know the voltage and current at those specific components. This information can be obtained through measurements or by using Ohm's Law (V = IR).

Once you have the voltage and current for each component, you can plug them into the power formula to calculate the power for C and E.

It is important to note that power is measured in watts (W), so make sure to use consistent units for voltage (volts) and current (amps) in the calculations.

I hope this helps with your issue. Let me know if you have any further questions.