Find the ratio of the energy of the La characteristic x-ray to the Ka

Thread starter ChrisWM
Start date Nov 6, 2020
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Characteristic Energy Ratio X-ray

Nov 6, 2020

ChrisWM

Homework Statement: Find the ratio of the energy of the La characteristic x-ray to the Ka characteristic x-ray for: a) Potassium b) Copper

Relevant Equations: 1/wavelength=R(z-1)^2*3/4
1/wavelength=R(z-7.4)^2*(1/4-1/n^2)
E=hc/wavelength

I found my energies for Potassium. I have 3.3 KeV for the k alpha nd 254.6 ev for L alpha, using z=19 and n=3. Are these values correct?
Edit: I found the ratio to be .077

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Nov 6, 2020

TSny

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Your answers look correct to me.

Nov 6, 2020

ChrisWM

TSny said:

Your answers look correct to me.

Thanks!

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