Find the ratio of the energy of the La characteristic x-ray to the Ka

Thread starter ChrisWM
Start date Nov 6, 2020
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Characteristic Energy Ratio X-ray

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The discussion focuses on calculating the ratio of the energy of the La characteristic x-ray to the Ka for Potassium, with specific values provided: 3.3 KeV for K alpha and 254.6 eV for L alpha. The user confirms the calculated ratio as 0.077. Other participants validate the accuracy of these values. The conversation emphasizes the correctness of the energy values and the resulting ratio. The findings contribute to understanding x-ray energies in elemental analysis.

Nov 6, 2020

ChrisWM

Homework Statement: Find the ratio of the energy of the La characteristic x-ray to the Ka characteristic x-ray for: a) Potassium b) Copper

Relevant Equations: 1/wavelength=R(z-1)^2*3/4
1/wavelength=R(z-7.4)^2*(1/4-1/n^2)
E=hc/wavelength

I found my energies for Potassium. I have 3.3 KeV for the k alpha nd 254.6 ev for L alpha, using z=19 and n=3. Are these values correct?
Edit: I found the ratio to be .077

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Nov 6, 2020

TSny

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Your answers look correct to me.

Nov 6, 2020

ChrisWM

TSny said:

Your answers look correct to me.

Thanks!

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