Find the ratio of the energy of the La characteristic x-ray to the Ka

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SUMMARY

The discussion centers on calculating the ratio of the energy of the L alpha characteristic x-ray to the K alpha x-ray for Potassium (Z=19). The participant reported energies of 3.3 KeV for K alpha and 254.6 eV for L alpha, leading to a calculated ratio of 0.077. The values provided were confirmed as correct by other participants in the discussion.

PREREQUISITES
  • Understanding of x-ray energy levels and transitions
  • Familiarity with characteristic x-ray emissions
  • Knowledge of atomic number and electron shell configurations
  • Basic skills in ratio calculations
NEXT STEPS
  • Research the principles of characteristic x-ray emissions in elements
  • Learn about the energy levels of electrons in Potassium
  • Explore the significance of K alpha and L alpha x-rays in spectroscopy
  • Study methods for measuring x-ray energies and ratios
USEFUL FOR

Students in physics or chemistry, researchers in material science, and professionals working with x-ray spectroscopy will benefit from this discussion.

ChrisWM
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Homework Statement
Find the ratio of the energy of the La characteristic x-ray to the Ka characteristic x-ray for: a) Potassium b) Copper
Relevant Equations
1/wavelength=R(z-1)^2*3/4
1/wavelength=R(z-7.4)^2*(1/4-1/n^2)
E=hc/wavelength
I found my energies for Potassium. I have 3.3 KeV for the k alpha nd 254.6 ev for L alpha, using z=19 and n=3. Are these values correct?
Edit: I found the ratio to be .077
 
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Your answers look correct to me.
 
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Likes   Reactions: ChrisWM
TSny said:
Your answers look correct to me.
Thanks!
 

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