Find the value of Cp using SFEE and Thermodynamic equations

AI Thread Summary
The discussion focuses on calculating the specific heat capacity (Cp) for a perfect gas undergoing isentropic expansion through a turbine. Participants clarify the relationships between Cp, Cv, and the gas constant (R), emphasizing that the molar gas constant is not dependent on the type of gas used. Confusion arises regarding the distinction between the universal gas constant and the specific gas constant, with participants noting that the problem lacks information on the gas's molar mass. Ultimately, a calculation yields Cp values around 20 kJ/kg/K, but participants seek methods to verify their results. The conversation highlights the importance of understanding thermodynamic equations and the properties of gases in these calculations.
Kajan thana
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Homework Statement
Find the specific heat capacity (Cp) with the given variables:

State:1.... p= 15 bars, Temperature: 600K,
State 2.... p= 1 bar, Temperature : 200, Enthalphy: -2000
This is an isentropic expansion.
Relevant Equations
Q-W=Cv(t2 -t2)
Cp/Cv= gamma
change in enthalphy = Cp * delta Temperature
I have managed to find the gamma value using the following equation: (T2/T1)= (P2/P1)(gamma-1/gamma. This will give me the answer of 1.29 SF. After this step, I am clueless.

Can someone help me with this question please?
I assume we have to find the enthalpy at state 1 to do that question.
 
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This is not the exact statement of the problem. Please provide the exact statement.
 
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Chestermiller said:
This is not the exact statement of the problem. Please provide the exact statement.

Calculate Cp for a perfect gas that undergoes isentropic expansion through a turbine from state 1 (600K, 15bar) to state 2 where the pressure is 1 bar, the temperature is 200K and enthalpy is -2000 kJ/kg (this number is calculated from the previous question) .
 
Kajan thana said:
Calculate Cp for a perfect gas that undergoes isentropic expansion through a turbine from state 1 (600K, 15bar) to state 2 where the pressure is 1 bar, the temperature is 200K and enthalpy is -2000 kJ/kg (this number is calculated from the previous question) .
OK. So the -2000 is irrelevant. What did you get for gamma?
 
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Chestermiller said:
OK. So the -2000 is irrelevant. What did you get for gamma?
gamma= 1.28
 
Kajan thana said:
gamma= 1.28
Kajan thana said:
gamma= 1.28
Sorry the gamma is 1.68
 
Kajan thana said:
gamma= 1.28
OK. From that, you should immediately be able to get Cp. How are Cp and Cv related to gamma and how are they related to R?
 
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Chestermiller said:
OK. From that, you should immediately be able to get Cp. How are Cp and Cv related to gamma and how are they related to R?
The relationships are Cp - Cv = R, and Cp / Cv = Gamma. But for this question they haven't mentioned the sort of gas that is used, so we cannot find the gas constant. I'm not sure how to find the Cv or Cp. In order to find the Cv, we need the work done or the change in enthalpy. I'm not sure how to go about doing it. Thanks
 
Kajan thana said:
The relationships are Cp - Cv = R, and Cp / Cv = Gamma. But for this question they haven't mentioned the sort of gas that is used, so we cannot find the gas constant. I'm not sure how to find the Cv or Cp. In order to find the Cv, we need the work done or the change in enthalpy. I'm not sure how to go about doing it. Thanks
You have two equations and 2 unknowns: Cp and Cv. The molar gas constant does not depend on the gas.
 
  • #10
Chestermiller said:
You have two equations and 2 unknowns: Cp and Cv. The molar gas constant does not depend on the gas.
Sorry I am bit confused. I thought that the molar gas constant was not the same as the universal gas constant (8.31). RGAS CONSTANT = R UNIVERSIAL CONSTANT/MOLAR MASS
 
  • #11
Kajan thana said:
Sorry I am bit confused. I thought that the molar gas constant was not the same as the universal gas constant (8.31). RGAS CONSTANT = R UNIVERSIAL CONSTANT/MOLAR MASS
The molar gas constant is equal to the universal gas constant. The mass gas constant is equal to the universal gas constant divided by the molar mass.
 
  • #12
Kajan thana said:
Sorry I am bit confused. I thought that the molar gas constant was not the same as the universal gas constant (8.31). RGAS CONSTANT = R UNIVERSIAL CONSTANT/MOLAR MASS
THE question doesn't have any information on the gas that is being used like the Molar Mass; apart from the mention of it being a perfect gas.
 
  • #13
Kajan thana said:
THE question doesn't have any information on the gas that is being used like the Molar Mass; apart from the mention of it being a perfect gas.
Cp they are looking for is the molar value, not the mass value.
 
  • #14
Chestermiller said:
Cp they are looking for is the molar value, not the mass value.
So with the simultaneous equation, I got the answer as 20 kJ/kg/K
 
  • #15
I get 20.5
 
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  • #16
Chestermiller said:
I get 20.5
yh I did the calculation wrong
Is there any other way to check the answer?
 
  • #17
Screenshot 2020-10-20 at 17.07.44.png
 
  • #18
I saw this on Wikipedia, where it mentions that Rspecific = Cp -Cv. Is there something that I am misunderstanding?
Thank you.
 
  • #19
You can express heat capacities per unit mole or per unit mass. The same goes for the gas constant. The gas constant per mole is the universal gas constant.
 
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  • #20
Chestermiller said:
You can express heat capacities per unit mole or per unit mass. The same goes for the gas constant. The gas constant per mole is the universal gas constant.
Thank you
 
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