Find the x-component of the magnetic force on the wire

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SUMMARY

The discussion focuses on calculating the x-component of the magnetic force on a wire carrying a current of 9.00 A along the z-axis in a uniform magnetic field with components Bx = -0.204 T, By = -0.968 T, and Bz = -0.328 T. The x-component of the magnetic force was determined to be 2.5 N, while the y-component was found to be -0.532 N. The force on the wire is calculated using the formula F_B = I L × B, where L is the vector representing the wire's direction and length. The discussion highlights the importance of understanding vector cross products in this context.

PREREQUISITES
  • Understanding of vector cross products
  • Familiarity with magnetic force equations
  • Knowledge of current-carrying conductors in magnetic fields
  • Basic calculus concepts for vector operations
NEXT STEPS
  • Study the vector cross product in detail
  • Learn about the Lorentz force law and its applications
  • Explore magnetic field calculations for different configurations
  • Review calculus applications in physics, particularly in electromagnetism
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Physics students, electrical engineers, and anyone involved in electromagnetism or studying forces on current-carrying conductors will benefit from this discussion.

Charanjit
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1. Homework Statement :
A wire with a length of 29.0 cm lies along the z-axis and carries a current of 9.00 A in the +z-direction. The magnetic field is uniform and has components Bx = -0.204T, By = -0.968T, and Bz = -0.328 T




Homework Equations


1. Find the x-component of the magnetic force on the wire. Ans: 2.5N
2. Find the y-component of the magnetic force on the wire Ans: -0.532N
3. Find the z-component of the magnetic force on the wire
4. What is the magnitude of the net magnetic force on the wire?



3. The Attempt at a Solution .
I solved question 1 and 2. But I don't fully understand why. For question 1 I used the force in the y direction and in 2 I used the force in the x direction. But why like that?
For #3, I used the z direction force, and its not correct. So kind of confused.
 
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The force on a wire in magnetic field B is given by

\vec{F_B} = I \vect L \times \vect B where L is a vector that points in the direction of the current and magnitude the length of the wire.

So,

\vec{L} = 0.29k
\vec B = -2.04i-0.968j-0.328k

Compute the cross product using a determinant.
 
Oh ok, kind of forgot myu calculus a bit. Read over my notes from Cal class, makes sense now. Thanks.
 

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