Find V(o) / V(s) in Output Opamp Voltage

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Homework Help Overview

The discussion revolves around determining the ratio V(o) / V(s) in the context of an operational amplifier circuit, with specific attention to the behavior of capacitors under different conditions.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of capacitors acting as open circuits in DC conditions and question whether this leads to V(o) being 0V. There is also consideration of using Laplace transforms for analysis. Others inquire about distinguishing between AC and DC sources based on circuit symbols and the presence of capacitors.

Discussion Status

Participants are actively discussing the nature of the input signal and its impact on the gain of the op-amp circuit. Some guidance has been provided regarding the interpretation of circuit symbols and the implications of capacitors in the feedback path, suggesting a potential AC signal.

Contextual Notes

There is mention of missing initial conditions and the need to clarify whether the input source is AC or DC, which remains a point of exploration in the discussion.

Abdulwahab Hajar
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Homework Statement


In the figure below find V(o) / V(s)

Homework Equations


In an opamp current doesn't enter through the inverting and non-inverting terminals, furthermore in DC conditions a capacitor acts like an open circuit

The Attempt at a Solution


The way I see it, both capacitors will act like open circuits current will have no path to follow...
therefore V(o) will be equal to 0V. also, no initial conditions are mentioned...
Is this correct?
or could this be done by a laplace transform??
figure is attached
Thank you
 

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Assume that ##v_s(t)## is an AC source. The gain will depend upon the frequency.
 
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gneill said:
Assume that ##v_s(t)## is an AC source. The gain will depend upon the frequency.
Got it, but how can I tell when it's an AC from a DC source
 
Abdulwahab Hajar said:
Got it, but how can I tell when it's an AC from a DC source
Usually they will use a slightly different symbol for the source.

upload_2017-5-8_14-52-28.png


In this case the presence of capacitors in the feedback path is a strong indication that some sort of signal filter is implemented, implying an AC input signal.
 
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