Find V(o) / V(s) in Output Opamp Voltage

AI Thread Summary
To find V(o) / V(s) in the given op-amp circuit, it's noted that capacitors behave as open circuits under DC conditions, leading to V(o) being 0V. The discussion highlights that the presence of capacitors in the feedback path suggests the circuit is designed for AC signals, which affects the gain based on frequency. Participants clarify that distinguishing between AC and DC sources often involves different symbol usage. The conversation also touches on the possibility of using Laplace transforms for analysis. Understanding these factors is crucial for accurate circuit analysis.
Abdulwahab Hajar
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Homework Statement


In the figure below find V(o) / V(s)

Homework Equations


In an opamp current doesn't enter through the inverting and non-inverting terminals, furthermore in DC conditions a capacitor acts like an open circuit

The Attempt at a Solution


The way I see it, both capacitors will act like open circuits current will have no path to follow...
therefore V(o) will be equal to 0V. also, no initial conditions are mentioned...
Is this correct?
or could this be done by a laplace transform??
figure is attached
Thank you
 

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Assume that ##v_s(t)## is an AC source. The gain will depend upon the frequency.
 
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gneill said:
Assume that ##v_s(t)## is an AC source. The gain will depend upon the frequency.
Got it, but how can I tell when it's an AC from a DC source
 
Abdulwahab Hajar said:
Got it, but how can I tell when it's an AC from a DC source
Usually they will use a slightly different symbol for the source.

upload_2017-5-8_14-52-28.png


In this case the presence of capacitors in the feedback path is a strong indication that some sort of signal filter is implemented, implying an AC input signal.
 
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