Find Vector Angle for Aircraft Flying N90KM with Wind 80KM/h

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An aircraft traveling at 300 km/h needs to reach a destination 90 km due north while contending with an 80 km/h wind from the west. The calculations suggest that the aircraft should fly at an angle of N15.467W to compensate for the wind. However, there is some discrepancy in the calculations, with one participant arriving at an angle of 14.9 degrees. The discussion emphasizes the importance of defining the velocity components correctly, with confusion over whether to use 300 km/h as the aircraft's airspeed or ground speed. Accurate vector analysis is crucial for determining the correct flight angle in windy conditions.
bayan
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Hi,
There is an aircraft moving at 300KM/h from its destination due north from an airport. It has to fly to the other airport(North) for 90KM.

The wind is blowing at 80KM/h from West to east.

At what angle must the aircraft fly to make its destination.


From my work out I found it to be N15.467W.

here is some work out.

let O=V wind

Let H=V aircraft

O/H=sin

Sin Thita=O/H
=80/300
Thita=Sin^1(80/300)
=Sin^-1(0.2667)
=15.467


Does this look right?
 
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I got 14.9 degrees.
 

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mtong said:
I got 14.9 degrees.


Did you use 300 as H or A?

The velocity is relative to Air.


I also had 14.93 but that was when I used 300 as A.
 
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