Find voltage using nodal analysis

AI Thread Summary
The discussion focuses on using nodal analysis to find the voltage V_2 in a circuit. The user initially struggles with applying Kirchhoff's Current Law (KCL) correctly at the nodes, leading to incorrect results for V_2. Suggestions emphasize the importance of maintaining consistent sign conventions when writing KCL equations to avoid mistakes. After correcting the equations by including the 10 V battery and adjusting the current directions, the user successfully calculates V_1 and V_2. The final values obtained are approximately V_1 = 10.24 V and V_2 = 13.90 V.
Martin V.
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Homework Statement


Assignment: Find V_2 using Nodal Analysis

Homework Equations


KCL
U=R*I

The Attempt at a Solution


- Chosen reference node
- Assigned node voltages
- Applied KCL to each non-reference node
- Solve system of equation
- Checked equations for obvious errors

See circuit drawing, node labels and assumed current direction in Nodal.png. Equation and solution of equation is to find in Nodal 2.png.

The right result should be that V_2=13,84V and not V_1 as I get.
 

Attachments

  • Nodal.png
    Nodal.png
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  • Nodal 2.png
    Nodal 2.png
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Not sure if this is the only mistake but KCL at node 2 is wrong...

Personally I prefer to write for my KCL equations to sum to zero so I would write...

Assume current leaving a node is +ve then..

+ I4 + I5 = 0
and
I4 = -I5

You might be tempted to skip steps but you have to be very fussy about the signs when applying KCL or KVL. I find I make fewer mistakes if I write my equation so it sums to zero and don't take shortcuts.
 
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Likes Martin V.
Your working for KCL at node 1 looks correct but I would write..

Assume current leaving the node is +ve..

-I1 + I2 +I3 = 0

Then rearrange it. It may seem fussy but by sticking to this version of the KCL definition I find I make few mistakes.
 
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Likes Martin V.
Both KCL-equations is wrong. With #2 is found the error in the equation around node 2. For node 1 were the 10 V battery not included in the equation. With the two change I get the correct answar - thanks! :)
 

Attachments

  • Nodal 3.png
    Nodal 3.png
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I agree with Martin V. I found ##V_1\approx10.2426...(V)## and ##V_2\approx13.9012...(V)##.
 
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