Find volume of object if cross-sections are known

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The solid in question has a base that is an equilateral triangle with an altitude of 14, and its cross-sections perpendicular to the altitude are semicircles. To find the volume, the formula V = ∫_a^b A(x)dx will be used, where the limits of integration are from 0 to 14. The radius of the semicircles varies linearly with x, starting at zero at x=0 and reaching R at x=14. To proceed, one must derive the equation for the radius in terms of x to calculate A(x) and perform the integration. Understanding the volume of revolution related to the shape can also help verify the final result.
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The base of a certain solid is an equilateral triangle with altitude 14. Cross-sections perpendicular to the altitude are semicircles. Find the volume of the solid, using the formula V= \int_a^{b} A(x)dx

applied to the picture shown attached to this post (click for a better view), with the left vertex of the triangle at the origin and the given altitude along the -axis.


i figure a= 0 and b = 14 and i will be plugging it into the formula pi*r^2 right?

the problem I'm having is finding the cross-section. can someone lend me a hand?
 

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You'll be integrating from x=0 to x=14 right?

First, find the length of one side of the equilateral, let's call it 2R.

It's clear at x=0, the radius is zero and at x=14 the radius is R, and the radius varies linearly with x. So set up an equation for the radius in terms of x.
then you can find A(x) and integrate.
 
Think of a volume of revolution formed by a general line y = mx. What sort of shape does this yield and how is it related to the shape you are given?

Thinking about this will also provide a good check as to whether your answer is correct as there is a nice formula for its volume.
 
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