- #1
UrbanXrisis
- 1,196
- 1
I need to find when 2x^3+x-5 is equal to zero and I'm stuck
2x^3+x-5=0
5=2x^3+x...then what?
2x^3+x-5=0
5=2x^3+x...then what?
The formula for solving this equation is known as the quadratic formula, which is (-b ± √(b^2-4ac)) / 2a. In this case, a=2, b=1, and c=-5.
The degree of this equation is 3, since the highest exponent is 3.
The possible solutions for this equation can be found by plugging in the values of a, b, and c into the quadratic formula and solving for x. In this case, the possible solutions are -1.618 and 1.118.
You can check your solutions by plugging them back into the original equation and seeing if they make the equation equal to zero. Additionally, you can use a graphing calculator to plot the equation and see if the solutions intersect with the x-axis.
Yes, there are other methods such as factoring or using the Rational Roots Theorem. However, the quadratic formula is the most reliable and efficient method for solving this type of equation.