Find y-component of Electric Field

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SUMMARY

The discussion centers on calculating the y-component of the electric field near a plane of charge located in the xz-plane at the origin, with a surface charge density of 4.57 µC/m². The electric field to the right of the origin is given as 520,000 N/C. Using the equation Enet = σ / (2 ε₀), the calculated electric field magnitude on either side of the plane is 258,070 N/C. The user incorrectly concludes that the left-side electric field (Eleft) is -261,930 N/C, leading to confusion regarding the net electric field calculation.

PREREQUISITES
  • Understanding of electric fields and charge distributions
  • Familiarity with the concept of surface charge density
  • Knowledge of the equation for electric fields due to infinite planes of charge
  • Basic algebra for solving equations
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  • Study the concept of superposition in electric fields
  • Learn about the permittivity of free space (ε₀) and its role in electric field calculations
  • Practice problems involving electric fields from multiple charge distributions
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Students studying electromagnetism, physics educators, and anyone seeking to understand electric field calculations near charged planes.

Erik1248
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Homework Statement



A plane of charge lies in the xz-plane at the origin. Its surface charge density is =4.57 uC/m^2; other charges are present in the vicinity as well. Just to the right of the origin the y-component of the electric field is 520,000N/C. What is the y-component of the electric field just to the left of the origin. Answer must take into account direction of field (left negative, right positive).

Eright = 520000
σ = 4.57 uC/m^2


Homework Equations



Enet = σ/ 2 ε0
Enet = Eright + Eleft



The Attempt at a Solution



I started with Enet = σ/ 2 ε0 = 258070
Eright = 520000
so via Algebra, Eleft = -261930

The sum of Eleft and Eright should be 258070,
what am I doing wrong?

Thanks...
 
Last edited:
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yo, erik welcome to physicsforums

I don't really understand the question. There is a plane of charge in the xz plane, going through the origin. OK, and just to the right of the origin, the y-component of the electric field is 520,000N/C I'm guessing that means the y direction is to the right?

You've got the equation Enet = σ/ 2 ε0 I don't know why you've called it Enet, because this equation tells you the magnitude of the electric field on either side of a plane of charge.

And you've got roughly the right answer for σ/ 2 ε0 = 258070 the magnitude of the electric field on either side of the plane of charge. But this doesn't make sense to me already, because this is in conflict with 520,000N/C as the value of the electric field.
 

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