Finding a vector perpendicular to a plane

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Miike012
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How did they know to do PQ cross PR instead of PR cross PQ?
And why did they not choose RP cross RQ?

Look at picture.
 
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  • 3D coordinate axes with a shaded triangle formed by points P(1, -1, 0), Q(2, 1, -1) and R(1, 1, 2), with vector arithmetic and a 3x3 determinant for PQ cross PR printed beside it.
    MATH QUESTION.jpg
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Miike012 said:
How did they know to do PQ cross PR instead of PR cross PQ?
Since any vector that is perpendicular to the plane will do, it doesn't matter if they calculate PQ X PR or PR X PQ, which will just point the opposite direction.
Miike012 said:
And why did they not choose RP cross RQ?

Look at picture.

If you cross any two vectors in the plane that aren't parallel, you'll get a third vector that is perpendicular to the first two.
 
Another question:
if I have 3 vectors u,v, and w
If i am trying to find u cross v cross w do i cross u with v first then w or v cross w then u?