Finding acceleration with circular motion

AI Thread Summary
When driving through a circular ramp at a constant speed, acceleration is determined by the formula a = v²/R. If the initial acceleration is 2.0 m/s², and speed is tripled while the radius remains constant, the new acceleration can be calculated using the same formula. Tripling the speed results in an acceleration that is nine times greater, leading to an acceleration of 18 m/s². The discussion emphasizes that no additional information about radius or initial speed is necessary to solve the problem. Understanding the relationship between speed and acceleration in circular motion is key to finding the solution.
David Mordigal
Messages
6
Reaction score
0

Homework Statement


Entrance and exit ramps for freeways are often circular stretches of road. As you go around one at a constant speed, you will experience a constant acceleration. Suppose you drive through an entrance ramp at a modest speed and your acceleration is 2.0 m/s2.

What will be the acceleration if you triple your speed?

Express your answer to two significant figures and include the appropriate units.

Homework Equations


a = v2/R

The Attempt at a Solution


Given that the initial acceleration is 2.0 m/s2, and a = v2/R...

I am not sure where to get started. R is not given, and v is not given. I know how to find a theoretically, but since I do not have concrete values to start with besides acceleration, I do not know where to begin.

Thanks for any guidance.
 
Physics news on Phys.org
Try this with R = 50 m, and with whatever velocity you need to give you a = 2 m/s2. Now, if you triple v, what do you get for a?

Chet
 
You don't actually need any more information, as you wrote yourself in a circular motion a = v2/R. now imagine, R is constant (because you are in the same road), you triple the speed, what will happen to acceleration?
 
OK, I got it. Thanks all for your help!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top