Finding Arc Length of c between (2,1,0) and (4,4,log2)

aligshah88
Messages
2
Reaction score
0

Homework Statement




Let c be the path c(t)=(2t,t^2,logt), defined for t>0. Find the arc length of c between the points (2,1,0) and (4,4,log2)

I just have a problem with the limits for the integral...what limits so I set for it after finding the derivative and using Pythagorean theorem...thanks.
 
Physics news on Phys.org
Let's start with the beginning, what's the formula for calculating the arc length??
 
If your only problem is limits of integration, you want (2t, t^2,ln(t))= (2, 1, 0) for the lower limit, (2t, t^2, ln(t))= (4, 4, ln(2)). Can you solve 2t= 2 and 2t= 4? (Because those points on the curve, those values of t must satisfy t^2= 1, ln(t)= 0 and t^2= 4, ln(t)= 1, respectively.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top