Finding area of the affine translation of a rectangle

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Homework Help Overview

The problem involves finding the area of an affine translation of a rectangle defined by specific coordinates and a transformation matrix. The subject area includes concepts from linear algebra and geometry.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the area of the rectangle and the application of the transformation matrix. There is confusion regarding the vectors used for calculating the area and the concept of crossing vectors.

Discussion Status

Some participants have provided guidance on the correct interpretation of the rectangle's dimensions and the appropriate vectors to use for area calculation. Multiple interpretations of the problem are being explored, particularly regarding the definition of vectors and the area calculation process.

Contextual Notes

There is a misunderstanding about the representation of the rectangle and the use of vector operations. Participants are questioning the definitions and methods applied in the area calculation.

yomakaflo
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Homework Statement


Given a rectangle R=[1,3] x [2,4], and the affin translation F : R^2 -> R^2 defined by F(x,y) = (1,3) + A*(x,y), where A is the 2x2 matrix (2 , 7 ; 3 , 1), what is the area of the affin transelation of the rectangle R?

Homework Equations

The Attempt at a Solution


When I cross the vectors of R I get the scalar 2. Is this the area of R before we transelate it? The determinant of A equals 19, and 2*19=38. So this is my answer and it is wrong. Right answer is 76, so I guess the area of R before translation should be 76/det(A)=4. Where am I wrong?
 
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The area of R is obiously 2x2=4 and it must be multiplied by 19 to get the translated area. What are the "vectors of R" that you crossed? Show us that.
 
R = [1,3] cross [2,4], so I think the vectors of R are [1,3] and [2,4] . When they are crossed the product is abs(4-6) = 2. I want the answer to be 4, but I don't know how!
 
yomakaflo said:
R = [1,3] cross [2,4], so I think the vectors of R are [1,3] and [2,4] . When they are crossed the product is abs(4-6) = 2. I want the answer to be 4, but I don't know how!

Those are not the correct vectors to cross. You want the vectors along the sides of the square.
 
yomakaflo said:
R = [1,3] cross [2,4], so I think the vectors of R are [1,3] and [2,4] . When they are crossed the product is abs(4-6) = 2. I want the answer to be 4, but I don't know how!
In addition to what LCKurtz said, those aren't even vectors -- they are intervals along the x and y axes. Also, I don't know what you are doing when you say you are "crossing" these vectors. The vector cross product is defined for vectors in R3.
 
Mark44 said:
In addition to what LCKurtz said, those aren't even vectors -- they are intervals along the x and y axes. Also, I don't know what you are doing when you say you are "crossing" these vectors. The vector cross product is defined for vectors in R3.

Okey, I misunderstood R = [1,3] x [2,4]. Then i makes sense that the area of R is 4 and 4*19=76 after the translation. Thanks!
 

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