- #1
sunnyday
- 6
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Homework Statement
A person jumps from the roof of a house 4.2-mhigh. When he strikes the ground below, he bends his knees so that his torso decelerates over an approximate distance of 0.66 m .
If the mass of his torso (excluding legs) is 43 kg , find the magnitude of the average force exerted on his torso by his legs during deceleration.
Homework Equations
vy2 = v02 +2ad
F=ma
The Attempt at a Solution
I already got 9.077 as v0 (this is correct)
vy = 0
d = 0.66
0 = 9.0772 + 2a(0.66)
-82.391 = 1.32a
a = -62.41F = 43(-62.41)
F = -2683.97 (this answer is wrong and I don't know why)