Finding Coefficient of Kinetic Friction for a Horizontal Force on a Wooden Desk

AI Thread Summary
To find the coefficient of kinetic friction for a block being pulled across a wooden desk, a horizontal force of 50 N is applied to maintain a uniform velocity. The net force is zero since there is no acceleration, indicating that the applied force equals the frictional force. The frictional force can be expressed using the formula: Friction Force = (Coefficient of friction) * (Normal force). Given the block's weight of 8.0 kg, the normal force is 78.4 N, leading to a calculated coefficient of kinetic friction of 0.64. This demonstrates the relationship between applied force, friction, and the coefficient of friction in a horizontal motion scenario.
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Homework Statement


A horizontal force of 50 N is required to pull and 8.0 kg block at a unifrom velocity across a horizontal wooden desk. Determine the coefficient of kinetic friction.


Homework Equations


F_{Net}=ma


The Attempt at a Solution


I put F_{Net} as 0, because accleration is 0. By doing this, I get the applied force and the force of friction both as 50, but I don't think that its right. By the way, the answer to the question is 0.64.
 
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You are correct in finding that the force applied is equal to the kinetic friction, but you need another formula to relate the frictional force to the coefficient of friction.
 
What would that formula be?
 
Friction Force = (Coefficient of friction)*(Normal force)
 
Thanks for the formula, I got the answer.:smile:
 

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