Finding Critical Numbers for a Polynomial Function with Power and Chain Rules

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1. Find the critical numbers of F(x) = x^{\frac{4}{5}}(x-4)^{2}



2. Power rule then chain rule



3. F'(x) = \frac{4}{5}x^{\frac{-1}{5}} (x-4)^{2}*2(x-4) I know two critical numbers are 0 and 4 and I am having problems finding the third one.
 
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frosty8688 said:
1. Find the critical numbers of F(x) = x^{\frac{4}{5}}(x-4)^{2}
2. Power rule then chain rule
and product rule?
frosty8688 said:
3. F'(x) = \frac{4}{5}x^{\frac{-1}{5}} (x-4)^{2}*2(x-4)
The first rule to use would be the product rule. It doesn't look to me like you used that rule.
frosty8688 said:
I know two critical numbers are 0 and 4 and I am having problems finding the third one.
 
Another way to do this is to write
F(x)= x^{\frac{4}{5}}(x^2- 8x+ 16)= x^{\frac{14}{5}}- 8x^{\frac{9}{5}}+ 16x^{\frac{4}{5}}
 
That makes it easier to understand.
 
Yes, but it would also be useful to use the product rule (correctly). The results should be the same for either method, but you might need to use some algebra to confirm that they are the same.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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