Finding Energy and Distance in a Hydrogen Atom using Uncertainty Principle

neelakash
Messages
491
Reaction score
1

Homework Statement



Is it possible to find out the minimum permitted energy of an electron in a Hydrogen atom and its corresponding mean distance from the nucleus using Uncertainty principle?

Homework Equations





The Attempt at a Solution



I know that if the mean distance is known we can find the energy... But,according to the question,we are to find both...
 
Physics news on Phys.org
Since you need to relate energy and distance, you have to consider the form of the Uncertainty Principle that includes position (units of length). What is the other related quantity? How might you use that quantity to find the electron's energy? (Hint: Consider the electron as being confined within a box the size of a hydrogen atom.)
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top