Finding final image through a lens

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The discussion focuses on determining the final image position through a lens and mirror system. The participant initially expresses confusion about the final image's location, noting that it is viewed from the left of the figure. They apply relevant equations to calculate the object distances and image positions, ultimately concluding that the final image is located R/4 to the right of point V. A request for clarification on the calculations is made, prompting further verification of the steps taken. The final consensus confirms the image's position as R/4 to the right of V.
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Homework Statement



An object is situated at various points relative to V. The light is then reflected by the mirror, and the final image is viewed by the observer.

http://www.flickr.com/photos/55153239@N03/6196518731/

Homework Equations



1/s + 1/s' = 2/R
na/s + nb/s' = (nb-na)/R

The Attempt at a Solution



The final statement of the problem confused me. It says the final image is viewed from the left of the figure. Therefore, you the mirror create an image inside the lens, and the light would then be refracted to the viewer outside the lens?

for d) I used the second equation to refract the light into the lens, to get s' = -3/2 R. This then acts as the object for the mirror a distance 5/2 R. Using the first equation, i get s' = 5/8 R. This would act as the object for the second refraction outside the lens. the end result is R/4 to the right of V. Is that correct?
 
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Hi coltin.walsh, welcome to PF.
"This would act as the object for the second refraction outside the lens. the end result is R/4 to the right of V."
Check this last step. Show your calculation.
 
so i would have s = 3/8 R. and using the second equation:

1.5/(3R/8) + 1/s' = 0
s' = -R/4
image is located a distance R/4 to the right of V.
 
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